2b^2-7=7

Solution for 2b^2-7=7 equation:

2b^2-7=7

We move all terms to the left:

2b^2-7-(7)=0

We add all the numbers together, and all the variables

2b^2-14=0

a = 2; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·2·(-14)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{7}}{2*2}=\frac{0-4\sqrt{7}}{4}
=-\frac{4\sqrt{7}}{4}
=-\sqrt{7}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{7}}{2*2}=\frac{0+4\sqrt{7}}{4}
=\frac{4\sqrt{7}}{4}
=\sqrt{7}
$